17 Pics about What is Electrical Current | Types and Measuring Units : GCSE-IGCSE Physics Electromagnetic induction - parts of the simple a.c, explain with diagram the flow of electric current in an electric and also Working or Operating Principle of DC Motor. The use of compact fluorescent lights (CFLs) saves up to 67% energy, and they may last 610 times longer than the regular incandescent bulbs. (2) (b) The washing machine is fitted with a fuse rated at 13 A. Equivalent resistance between A and B is = 2+R+5Where 1/R = 1/10 + 1/10 = 2/10 = 1/5Equivalent resistance between A and B = 2+5+2= 12 [ANS]. We know that P= V X 1From Ohms law, we haveV/I = ()Or V= IROr =V/I . =*E/r17) Melting point of tungsten is about 30000C.18) The number of electrons contained in one coulomb of charge is 1.6 X 10-19.19) Value of specific charge on an electron is 6.25* 10-18C.20) The SI units for electric intensity are NC-1.21) 1 KWh is equivalent to 3.6 X 106J. e.g., Mercury, niobium, etc. (iii) Nature of the Material of the Conductor : The resistance of a conductor depends on the nature of the material of which it is made of. There is a continuous drop in potential all along in series circuit, but potential difference goes on increasing. The electric current, in a given conductor is simply the rate of flow of charge across its cross section. = E/R Where E=1.5 V and R1 = 3.0 Current i = 1.5V /3.0 = 0.5 A [ANS], (iii) The drop in potential across the terminal of a cell V= E- irp= 1.5 V 0.5 A X 0.5 = 1.5 V -0.25 V = 1.25 V [ANS], Which is same across the terminal of every cell as the other specification of different cells are sameOr =ER/rp+R= 1.5V X 2.5V / 0.5+2.5=1.5V X 2.5/3.0=1.25V(Am) [ANS], 53) In the figure shown below calculate (2000)(i) The value of combined resistances of 40 Ohm and R using the reading of the two meters(ii) The value of R(iii) The current flowing through R, Given V= 4.0 V and I =0.4 A(i) Therefore the total resistance of the circuit is R=V/I = 4.0/0.4 = 10 ohm [ANS], (ii) Now R and 40 Ohm are connected in parallel and their combined resistance is 10 Ohm therefore we have1/10 = 1/R+ 1/40 solving for R we have R = 40/3 = 13.3 ohm, (iii) Current flowing through R = 0.4 X 40 /40 +13.3 = 0.3A [ANS], 54) Define the e.m.f (E) of a cell and the potential difference (V) across a resistor (R) in terms of the work done in moving a unit chargeState the relating between these two works and the work done in moving a unit charge through a cell connected across the resistor. [ANS]5) Calculate the equivalent resistance of the following combination of resistors r1, r2, r3 and r4, The resistors r3 and r4 are in parallel if r is equivalent resistance of resistors r3 and r4 then, Now resistors r1, r2, and r3 are in series equivalent resistance. . This is a consequence of the conservation of charge. Thus,I = Q/t, The unit of current is ampere (A). And the unit of current is amperes, or amps, A. CREDITSAnimation \u0026 Design: Chloe Fyvie AdamsNarration: Dale BennettScript: Bethan ParrySUBSCRIBE to the FuseSchool YouTube channel for many more educational videos. 61) Write an expression for the resistance of a conducting wire in terms of its length and area of cross sectionR= (1/A), where r = resistanceL= length andA = Area of cross section of the wireP = resistivity or specific resistance of the material of the wire. (ii) What is the current through R? Chemical energy is converted into electrical energy. Current in external circuit= Total E.m.f Total resistance of circuit =nE/R+nr. Since electric current is the passage of a net charge across a region, there is a formula to calculate it and your O level syllabus requires you to learn this formula. [ANS]. You can both ask and answer questions, and teachers will get back to you.These videos can be used in a flipped classroom model or as a revision aid. We have1 A = 1 coulomb per second = 1 Cs-1. *This Course is about Extended Cambridge (0625) IGCSE Physics. (ii) What is the potential difference across the terminals of the cell?Given E= 2V, r = 1.2 Resistance of resistor A= 0.8 Resistance of resistor B= 4.5 Resistance of resistor C=9 The resistors B and C are in parallel. Resistance wire, resistance box, rheostat or variable resistance:A resistance wire is made up of an alloy of nichrome and has a fixed resistance value depending on its length and thickness. Hence it will reduce the current in the circuit, so each appliance will get less power. Current at point B is also I. 5) Unit of electric charge: The unit of electric charge is coulomb one coulomb is equivalent to total change 6.25* 1018 Electrons. 5. (2015). Its SI unit is volt (V). P.D = W/q i.e., work done in moving a unit positive change across the terminals of the cell. When the resistance is varied by sliding the jockey of the rheostat, the glow of the bulb changes and so do the readings on the ammeter and voltmeter. Electric current - The amount of charge flowing through one cross section of a conductor is called Electric current. Students can refer to the quick revision notes prepared for Chapter Electricity in Class 10 ICSE. This confirms the Ohms law. According to Ohms Law :The current flowing through a given conductor is directly proportional to the potential difference across its ends, provided the physical conditions of the conductor (e.g., its length, its area of cross-section, its temperature, etc.) Learn about and revise mains electricity, current and the role of the National Grid with this GCSE Bitesize Physics. (ii) The wires carrying current should be having higher capacity than the total current which would flow when all the appliances are switched on. (a) In order to increase the resistance of a circuit resistors are connected in series. Current electricity is generated by power plants and batteries. Scribd is the world's largest social reading and publishing site. Electric charge can also be thought of as the movement of electrons. V= V1+ V2+V3. Lindsay graduated with First Class Honours from the University of Greenwich and earned her Science Communication MSc at Imperial College London. It is a scalar quantity. Current Electricity ICSE Class 10 Physics Revision Notes Revision Notes A sustained electric current flows through a conductor only when it is connected to a source of emf. Electrons move faster at A. The regular pencil cells used in daily life provide a direct current. Calculate the equivalent resistance of the combination between any two adjacent corners.The diagram indicates a square ABCD formed by joining four resistance of 2 each end to end let us calculate the equivalent resistance of the combination between the two adjacent corner C and D.Let us calculate the equivalent resistance of the combination between the two adjacent corners C and D. Arms DA AB and BC are joined in series so their equivalent resistance=(2+2+2) 6 now resistance of 6 and 2 are in parallel The equivalent resistance of the combination is RThen, 1/R = 1/6+ 1/2 = 4/6 = 2/3, 49) In the fig given alongside A, B and C are three ammeters. Given specific resistance of Eureka = 49= 10-8 ohm-m.Here L= 110 cm = 1.10m,r=0.1 mm= 10-4 m,p= 49 X 10-8 ohm .m, 14) Four cells each of 1.5 volt e.m.f and 20 ohm internal resistance are used to send a current through a wire of 20 ohm resistances. Find the resistance of the combination in each case.R1 = 2 ohm, r2 = 4 ohm, Rp =? 3. 2. 7) Calculate the resistance between the points X and Y in the given figure below. Part1: Basic Electricity, Part 2: Electromagnetism, Part 3: Electronics, This course is only part 1 Basic Electricity, other parts will be in other courses, When a cell of emf , and internal resistance r, is connected across an external resistance R, current flows through the circuit. 38) (a) An electric bulb is marked 100 250 V what information does this convey? The electricity built on the surface of a substance is known as static electricity. The obstruction offered to the flow of current by the conductor (or wire) is called its resistance. A sustained electric current flows through a conductor only when it is connected to a source of emf. Connecting wires:The wires used to connect different electrical components are called connecting wires. This color code of electric wire must be followed, so that even a layman will be able to identify the correct connecting wire. A socket is fixed in the board of the circuit so that plug can be inserted. 6) The equivalent resistance of the following circuit diagram is 4 calculate the value of X .Resistance of 5 and X are in series.Similarly, resistance of 8 and 4 are in series.Equivalent resistance. across the parallel combination of resistors = 12-8= 4 VThe resistances are in parallel they have the same P.D each i.e., 4 V [ANS], (c) Current through the 6 resistor 4/6 = 2/3 A= 0.67 [ANS]. IGCSE Physics 0625 notes Topic 4: Static Electricity 5 also the larger units of power are 1 kilowatt (kW) = 1000 W Resistance is calculated by dividing the voltage between two points by the current flowing through the . having 66 A and A stars in CAIE O Level, IGCSE, A Level, Pearson Edexcel GCSE and IAL education. 1. material that has low resistance to the flow of electric current 2. electric current that flows in only one direction 3. opposition to the flow of electric current 4. material that has high resistance to the flow of electric current 5. any continuous flow of electric charges due to a difference in voltage If you have any questions please post them in the comments section below, ICSE Class 10 Previous Year Question Papers, Electric Power and Energy, Fuse, Household Circuit, Sample Paper ICSE Class 10 Mathematics Set F, Soil Resources Previous Year Questions ICSE Class 10 Geography, Rise of Assertive Nationalism ICSE Class 10 Board Exam Questions And Answers, Notes For ICSE Class 10 Economics Commercial Banks, Daffodils Summary and Important Questions, Selina ICSE Class 10 Physics Solutions Chapter 4 Refraction Of Light At Plane Surfaces, Selina ICSE Class 10 Physics Solutions Chapter 11 Calorimetry, Selina ICSE Class 10 Physics Solutions Chapter 10 Electro Magnetism, Selina ICSE Class 10 Physics Solutions Chapter 2 Work Force And Energy, Selina ICSE Class 10 Physics Solutions Chapter 3 Machines. (b) What name is given to this phenomenon? Proper placement of windows and use of features which reflect light into a building can reduce the need for artificial light. Galvanometer:A galvanometer is used in a circuit when a small current is to be measured or to know the direction of flow of current. The following diagrams illustrate a dual switch with two switches S1 and S2. (i) The potential difference across each resistor is the same (V1 = V2 = V3 say) which is equal to the potential difference across the terminals of the battery (or source). (iii) What will be the ammeter reading if an exactly similar cell is connected in series with the given cell? and the terminal voltage of cells : When the resistance of the combination is to be increased, they are combined in series and when the resistance of the combination is to be decreased, in order to pass a heavy current in the circuit, they are combined in parallel. V-I graph :The below graph gives the graphical representation of Ohms law where the slope of V-I graph gives the resistance of the conductor. Electricity and Magnetism. 46) A Wire of uniform thickness with a resistance of 27 is cut into three equal pieces and they are joined in parallel. Draw a labeled circuit diagram showing the above arrangement and the current drawn from the cell. ICSE Revision Notes for Current Electricity Class 9 Physics Current Electricity Sources of Direct Current The regular pencil cells used in daily life provide a direct current. Electric current is the rate (amount) of flow of electric charge: I = Q / T I = Current (in Ampere) Q = Charge (in Coulomb) t = Time taken (in seconds) The use of advanced boilers and furnaces in industry can save sufficient amount of energy in attaining high temperature by burning less fuel. E.m.f of a cell = 1.5 voltInternal resistance = 1.0 Ohm (r)External resistance = r1+ r2( in series), (i) Current I = E/r+R or l = 1.5 / 1+24 = 1.5/25 = 0.6amp [ANS](ii) P.D across 4 resistor = 4 X .06 = .24 Volt [ANS](iii) Voltage drop when the current is flowing = Ir = 06 X 1 = .06 Volt [ANS](iv) Potential difference across the cell = RI = 24 X .06 = 1.44 volt [ANS], 45) In the figure below, the ammeter A reads 0.3 A. 6) The charge on one electrons is equivalent to 1.6*10-19C. They are unreactive metals, which are called inert electrodes because they do not react with the products of electrolysis. He is currently the World Record Holder, having 66 A and A stars in CAIE O Level, IGCSE, A Level, Pearson Edexcel GCSE and IAL education. Thus, the resistance of the conductor is numerically equal to the potential difference across its ends when unit current flows through it.R = V/I or V = IR or I = V/R. in parallel to the flow of current. an electric current that flows in one direction steadily. Given I1= 0.6A, R1= 2,I2= 0.3 A, R2= 8 , r =?Using I = E/R+r1) 0.6 = E/2+r and2) 0.3 = E/8+r, From the above two we haveAs same cell is usedE is same so (i) = (ii)0.6(2 + r) = 0.3 (8+ R)Or 0.3r = 1.2 or r = 4OhmE= 0.6(2+4) (putting the value of r in eq. (ii) Let current through 4 resistance is iThen current through 6 resistance is(0.5-i)i X 4 = (0.5-i) X 6 or4i=3-6iOr 10i = 3 or i =0.3ACurrent through 4 resistance = 0.3 A and current through 6 = 0.5-0.3= 0.2 A (Am) [ANS], 30) A metal wire of resistance 6 is stretched so that its length is increased to twice it original length, calculate its new resistance?Volume of a metal wire remains same, 31) Calculate the equivalent resistance between the points A and B for the following combination of resistance, Resistance between A and B R=5+2+6= 13 Hence equivalent resistance between A and B = 13 [ANS], 32) An electrical application is rated at 1000 KVA, 220 V if the application is operated for 2 hours calculate the energy consumed by the application in (i) kwh (ii) joule. The use of fluorescent lights or natural skylight instead of the traditional incandescent light bulbs reduces the amount of energy required to attain the same level of illumination. (ii) The current flowing in the external circuit in parallel combination of the cells, the effectivee.m.f of any number of cells is equal to the e.m.f due to a single cell. Description. with the mains :We note that all the electrical appliances (say, bulbs, fans, sockets, etc) are connected in parallel at the mains, each with a separate switch and a separate fuse connected in the live wire. Advantages of connecting the appliances in parallel :(i) Each appliance gets connected to 220 V supply (= its voltage rating) for its normal working. the equivalent resistance of 4 and 8 in parallel is given by, 1/R = 1/4 + 1/ 8 = 2+1 /8 = 3/8 OR R = 8/3 = 2.67, Thus, the total resistance of the setup is (2-67+10) = 12.67 [ANS]Fig. 2) What should be the length of nichrome wire of resistance 5 if the length of similar wire is 60 cm and resistance 2.5 ?1 = 5 , L2 = 60 cm, R2 = 2.5 , L1 = ? The conductor which does not obey Ohms law is known as non-ohmicresistor for non-linear resistance) e.g., Triode valve, junction diode, transistor, etc. A buildings location and its surroundings play a key role in regulating its temperature and illumination. Clearly AE= EC=CD=DE=BD=10 CMTherefore R1= R2 =R3 =R4 = R5 =10 As R2 and R3 are in series therefore their combined resistance is 10+10=20 Ohm This combination is in parallel with R5. 25) A battery of emf 12V and internal resistance 2 is connected with two resistances A and B of resistance 4 and 6 respectively joined in series. Electric current is the rate of flow of electric charge. The electric current, in a given conductor is simply the rate of flow of charge across its cross section. Calculate the (a) reading of ammeter and (b) Readings of V1 , V2 and V3E = 24 V. Resistance of 6 and 3 are in parallel. The current, flowing through a wire, is said to be one ampere when one coulomb of charge flows across its cross-section in one second. 1) An experiment is performed to verify ohms law observations and tabulated and follows. The circuit can be switched on either using switch S1 or S2. E= i (R+ r)1.5 = I (5+10) or i= 1.5/1.5I = 0.1 A [ANS], 52) Four cells each of e.m.f 1.5 V and internal resistance 2.0 Ohms are connected in parallel.The battery of cells is connected to an external resistance of 2.5 Ohms. 7) Potential difference: Potential difference between two points in an electric circuit is the amount of work done to move certain amount of change from one point to another point.Potential difference (v) = Work done(w) / Amount of charge (Q). 3) Calculate the equivalent resistance between point A and C, as show in figure. Current electricity is generated and used as a source of energy in homes and industry. Selina Physics ICSE Solutions for Class 9. The upper bigger hole is for earth connection, the left is for neutral and right for a live wire. Our teachers have prepared these concept notes based on the latest ICSE syllabus and ICSE books issued for the current academic year. remain constant. The notes contain an overview and question answers of the chapter. 9) Parallel circuit: When a number of resistors are connected such that they have a common positive and a common negative terminal then resistors are said to be in parallel circuit.The potential difference in a parallel circuit is a constant quantityThe current divides in parallel circuit in the inverse ratio of resistanceTotal current flowing through parallel circuit is equal to the sum total of current flowing through individual resistors.i.e. Why is it so important?The following is the color code.Live wire- red, Neutral wire black and earth wire Green. Sources of current:Current is of two types alternating (or AC) and direct (or DC). GCSE exams June 2018 onwards. this video includes definition of current, charge, q=it. [ANS]. Static electricity is generated when objects are rubbed against each other resulting in charge transfer. across 8 resistor = 1 X 8=8 VP.D. W = QV. Work out the current flowing through the 10 and the total voltage of the cell. Step 2- Charge a balloon, by rubbing it on your hair or clothing. close menu Language. The key completes the circuit. Find:i. current in the circuitii. Resistivity of a material is the resistance of a wire of that material of a unit length and unit area of cross section. The cells are arranged (i) all in series (ii) all in parallel. 40.8 V 4. Efficient use of energy means to reduce the cost and amount of energy to be used to provide us the various products and services. The total number of distinct A grades he got are 154. And V =?By Ohms law the current through resistor of 5 ohm is, (ii) Since the two resistors are connected in series therefore the current through resistor R is also 2 ampere [ANS], (iii) Therefore value of R can be obtained as follows.R = V/1 = 6/2 = 3 Ohm [ANS], (iv) Since the resistors are in series therefore, net resistance of the circuit isR=R1+R2=5+3=8 Hence by the expression of V=IR we have V= 2X8= 16V [ANS], 17) A letter A consist of a uniform wire of resistance 1 ohm per cm the sides of the letter are each 20cm long and the cross piece in the middle is 10 cm long (P-8.50). (ii) Area of Cross-Section of the Conductor : The resistance of a conductor R is inversely proportional to its area of cross-section A.i.e., R 1/A. Ohmic and Non-Ohmic Resistor :The conductor which obeys Ohms law is called ohmic resistor (or linear resistance), e.g., Silver, nichrome, copper,iron etc. (2011), Let 12 and 6 resistors are in parallel.Their effective resistance = 12X6 /12+ = 72/18 = 4Total resistance of the circuit = 8+4 = 12 So current drawn = 12/12 = 1A, (a) Current through 8 resistor = 1 A [ANS], (b) P.D. An electric current flows when electrons move. [ANS]. (iii) Each appliance must be provided with a fuse. Specific resistance =? 16) Cell can give maximum current in parallel only if external resistance is very small and internal resistance is large. You cannot access byjus.com. This direction is opposite to the direction of flow of electrons. No current can flow if the circuit is broken - for example, when a switch is open. As the polythene gains electrons it becomes negatively charged. (b) What is the potential difference across the parallel combination of 6 Ohm and 12 ohm resistor? When a positively charged conductor is joined by a metal wire to a negatively charged conductor, the electrons flow from the negatively charged conductor to the positively charged one. Internal resistance decreases with increasing temperature or concentration of an electrolyte.Factors Affecting the Resistance of a ConductorThe electrical resistance of a conductor depends on the following factors :(i) Length of the Conductor : The resistance of a conductor R is directly proportional to its length li.e., R l, When the length of a wire is doubled or halved, then its resistance also gets doubled or halved respectively. Examples: Simple voltaic cell, Daniel cell, Examples: Lead accumulator, NiFe accumulator. The size of the electric current is the rate of flow of electrical charge. One kilowatt-hour (kWh) is the electrical energy consumed by an electrical appliance of power 1 kW when it is used for 1 hour.1 kWh = 1000 W 3600 s= 3.6 106 J, Electrical energy consumed by appliance (in kWh) = power (in kW) time (in h) = power (in watt) time (in hour) 103 = V (volt) I (in ampere) t (hour) 103. 29) Two resistors of 4 and 6 are connected in parallel to a cell to draw 0.5 A current from the cell (2014)(i) Draw a labeled circuit diagram showing the above arrangement(ii) Calculate the current in each resistor. Topic 1: General Physics. The higher the current, the faster the electrons are travelling. Relation between E, V external resistance R and the internal resistance r Applying Ohms law to external resistance only ; I = V/R . across parallel circuit; V = IR = 0.3 X 1 = 0.3 V, Current in 6 resistorI1 = V/R = 0.3/6 = 0.05 A[Ans. Students should refer toCurrent ElectricityICSE Class 10 Physics Notes and solutions below. (2016), (i)Total resistance = (4.0+6.0+2.0) = 12 Current in the circuit = V/R = 12/2 = 1 [ANS], (ii) Terminal voltage of the cell V=IR = 1 X 10= 10V [ANS], (iii)The potential difference across 6 Resistor = I X R = 1A X 6 =6 V [ANS], 26) Find the equivalent resistance between point A and B. (iv) Effects of Temperature :(a) Resistance of a conductor increases linearly with increase in temperature. If you would like to use the video, please contact us: info@fuseschool.org A conductor has a resistance of one ohm when a potential difference of one volt across its ends causes a current of one ampere to flow through it. The resistance associated with the electrolyte of a cellwithin its electrodesis known as the internal resistance of the cell. )(ii) Conducting wires or conductors for providing a path for the flow of current and(iii) A switch or a key for switching ON and OFF electric energy as per our requirements. SI Units : By the definition of potential difference, work needed to move a charge Q through a potential difference V is W = QV But Q = I t W = VIt Using Ohms law, W = I2 Rt = (V2 /R) t The unit often used for estimating the consumption of electrical energy is the kilowatt hour (kWh). If the answer you have written is not right, change it . across 6 = P. D. across 3 or 6 X 0.5 = 3 X i.e, Or i c i.e., current passing through the ammeter c is (6 X 0.5)/3 = 1.0 ampere [ANS], (ii) Here 1/R = 1/6 + 1/3 = 3/6 = 1/2 = 2 , Total resistance of the circuit = 2 + r = 2 + 2 = 4 , Current through A = Current passing through B+ current passing through CCurrent through A = 0.5 +1.0 = 1.5 ampere. Potential difference between two conductors is equal to the work done in transferring a unit positive charge from one conductor to the other through the metallic wire. Kinds of Cells Electric Current Current (I) = Charge (Q)/Time (t) It is a scalar quantity. When it is open, the bulb does not glow, and the ammeter and voltmeter do not show any reading. So, the equivalent resistance in a series combination is the sum of all resistances. Combination of resistors in Parallel : Three resistors R1, R2 and R3 are connected in parallel. English (selected) 12) Q when do we join resistors in (a) series (b) parallel. Papers 1-6. (i)= 3.6 V [ANS], 60) From the given figure above calculate (1996)(i) The equivalent resistance between P and Q(ii) The reading of the ammeter(iii) The electrical power between P and Q, (i) if equivalent resistance is R, then1/R = 1/4+ 1/6 = 3+2/12 = 5/12Equivalent resistance R = 12/5 = 2.4 [ANS], (ii) From diagram E= 2 X 2 = 4 V and R=2.4 But E = IR4 = I X 2.4I= 4/24 = 1.66 A [ANS], (iii) P = I2R = (4/24) X 2.4 = 6.66 watts [ANS]. Short Notes for revision of ICSE Class 10 Chapter 8 Current Electricity Below are some short notes on the above topics. So, the reciprocal of equivalent resistance in a parallel combination is equal to the sum of reciprocal of individual resistances. The potential difference between two points equals one volt if the work done in transporting a charge of one coulomb between these points equals one joule. (b) This phenomenon of loss of electrical resistance of a substance on cooling it to an extremely low temperature is known as super conductivity.24) Derive the formula for electric power which is used only when voltage V and resistance R are known to us. It is to be connected across two points, i.e. IGCSE Physics Solutions (Answers) 1. i) Right to left ii) +ve terminal to -ve terminal 2. There is always some obstruction in the current which flows through a conductor such as a metal wire, and this obstruction is called its, According to Ohms law, if current I flows through a wire when potential difference across the ends of a wire is V, then the resistance offered by the wire is. A and B, Let I be current flowing through R then (0.3-1) is current flowing through 60 resistances, Now V= V I1 R1 = I2 R2I1 X 30 = (0.3- I1) X 60I1 = 0.6 2 I, or 3 I1 = 0.6or I1 = 0.6/3 = 0.2Current flowing through R= 0.2 A [ANS]. CURRENT ELECTRICITY Physics 94 and the quotient q I t = (3.1) is defined to be the currentacross the area in the forward direction. The two 10 resistors are in series & parallel to 5 equivalent resistance1/R = 1/20 + 1/5 = 1+4/20 = 5/20 = 1/4R = 4Resistance between P and Q = 3+4+2= 9 [ANS], 34) At what voltage is the alternating current supplied to our house?220 to 240 V, 35) Three resistors are connected to a 6 V batter as shown in the given figure (2011)(i) Calculate the equivalent resistance of the circuit(ii) Total current in the circuit(iii) Potential difference across the 7.2 resistor, (i) 8 and 12 are in parallel, then equivalent resistance1/R = 1/8 + 1/12 = 5/24 R=4.8, Now total resistance = 4.8+7.2= 12 [ANS](ii) Let V= IR = V/R = 6/12 = 0.5A [ANS](iii) P.D across 7.2 = 0.5 X 7.2= 3.6 V [ANS], 36) Calculate the equivalent resistance between A and B from the following diagram. Cost of electricity = electrical energy in kWh cost per kWh Colour coding of wires in a cable : A fuse is a safety device which limits the flow of current in a circuit and thus protecting the device from being damaged. Fuse is made up of material having low melting point. A switch is an ON/OFF device which is connected in a circuit to the live wire. Earthing protects the appliance from getting damaged due to excessive current. The graph of V vs I a curved line. Direct current is a current of constant magnitude flowing in one direction. Safety precautions while using electricity :(i) Never touch the appliance with wet hands. Its SI unit is ampere (A). current-electricity (edexcel igcse) - Read online for free. Currents are not always steady and hence more generally, we define the current as follows. I = /(R + r) and V = p.d. across R = IR, The internal resistance of a cell depends on(iv) the nature, concentration and temperature of its electrolyte. ICSE Rankers is a free educational platform for ICSE and ISC k-12 students. It is a scalar quantity. Three resistors R1, R2 and R3 are connected in parallel. , Rs =? Nowadays appliances are star rated according to their efficiency in using electricity. We have (2015), 12 , 6 And 4 are connection in parallelThen 1/RP = 1/12 + 1/6 + 1/4 = 1+2+3 /12 = 1/2Rp = 2, Now 2 , 2 and 5 are combined in a seriesThen equivalent resistance between point A and B, R= (2+2+5) =9 [ANS], 27) A cell of E.m.f 2v and internal resistance 1.2 is connected with an ammeter of resistance 0.8 and two resistors of 4.5 and 9 as shown in the diagram below.
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